Coronavirus outbreak: Air India special flight to evacuate Indians today from Wuhan
The Jumbo 747 is a 423-seater airplane that will fly to Wuhan from Delhi for evacuating Indian citizens.
January 31, 2020 / 11:23 AM IST
National airline carrier Air India is set to rescue over 250 Indians from the locked-down city of Wuhan in China. The airline’s Jumbo Boeing-747 will depart from Delhi airport at 12.30 pm, as per a senior airline official.
Air India’s national spokesperson Ashwani Lohani tweeted, “The national carrier once again comes to the rescue - this time to evacuate Indians from Wuhan, the site of the outbreak of coronavirus. This mission begins today with a Jumbo 747 operating between Delhi and Wuhan.”
The Jumbo 747 is a 423-seater airplane that will fly to Wuhan from Delhi for evacuating Indian citizens. The evacuation comes a day after India confirmed its first case of Coronavirus in Kerala.
An Indian student, who was studying at the Wuhan University, was found positive in Kerala, the health ministry noted.
Earlier, the Ministry of External Affairs (MEA) had seemed permission for operating two flights to bring back Indian citizens from the virus-affected city in China. The MEA has also reached out to over 600 Indians living in the Hubei province.
MEA spokesperson Raveesh Kumar said that there is not any report of any Indian being infected by the coronavirus in Hubei province or any other country. Kumar also confirmed that there is no restriction on Indians returning to India from China following the outbreak.
As a precautionary measure, Air India and Indigo have suspended their commercial operations from India to China starting January 31; which will be in place until February 14.